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Question 422248: How do I solve
2a/a^2-9 + a/a-3
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! "How do I solve
2a/a^2-9 + a/a-3 "
2a/a^2 - 9 + a/a - 3
= 2a/(a + 3)(a - 3) + a/a - 3 {factored a^2 - 9, it is a difference of two squares}
= 2a/(a + 3)(a - 3) + a(a + 3)/(a + 3)(a - 3) {got a common denominator of (a + 3)(a - 3)}
2a + a(a + 3)
-------------- {wrote vertically to see better}
(a + 3)(a - 3)
2a + a^2 + 3a
------------- {used distributive property}
(a + 3)(a - 3)
a^2 + 5a
-------------- {combined like terms}
(a + 3)(a - 3)
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