Question 404569: consider the function f(x)=x^2+6x-2. find h, the x-coordinate of the vertex of this parbola. Substitute the two intergers immediately to the left of h and two intergers immediately to the right of h into the function to find the corresponding y values. Fill in the table below, make sure your x-values are in increasing orders in your table. x y there are 5 boxes under each of these. In the 4th box under x is h=____. I have to graph this so any help with that too will be greatly appreciated. Thanks abunch.
Answer by josmiceli(19441)   (Show Source):
You can put this solution on YOUR website! The x-coordinate of the vertex of a parabola is at
 , where the equation is in the form:
In the given equation:
Now plug this back into equation to get 
So the vertex is at the point h = (-3,-11)
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I'm not sure what the table is supposed to look like.
It sounds like they want
(-3,-11) (vertex)
(-4, f(-4))
(-5,f(-5))
(-6,f(-6))
etc., and, in the (+) direction from the vertex:
(-2, f(-2))
(-1,f(-1))
(0,f(0))
(1,f(1))
etc.
Here's a plot of the equation. Maybe you can
figure out the table.
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