SOLUTION: (6x^2+7y-20) how do I factor?

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Question 402761: (6x^2+7y-20) how do I factor?
Answer by sofiyac(983) About Me  (Show Source):
You can put this solution on YOUR website!
Did you mean 6x^2+7x-20??? Becaues the way you wrote it there's nothing to factor. To solve for x you can either use quadratic formula or complete the square. Formula is easier.
6x^2+7x-20=0
a=6, b=7, c=-20
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-7+%2B-+sqrt%28+7%5E2-4%2A6%2A-20+%29%29%2F%282%2A6%29+
x+=+%28-7+%2B-+sqrt%28+49%2B480+%29%29%2F%2812%29+
x+=+%28-7+%2B-+sqrt%28+529+%29%29%2F%2812%29+
x+=+%28-7+%2B-+23%29%2F%2812%29+
x+=+%28-7+%2B+23%29%2F%2812%29=16%2F12=4%2F3
or
x+=+%28-7+-+23%29%2F%2812%29=-30%2F12=-5%2F2+
So those are your roots.
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6x%5E2%2B7y-20 you can try completing the square on it as well
6x%5E2%2B7x-20=0
6x%5E2%2B7x=20
6%28x%5E2%2B7x%2F6%29=20 so we need to add (7/12)^2 in order to complete the square. But we have to account for that 6 up front, so in reality we are adding 49/24
6%28x%5E2%2B7x%2F6%2B%287%2F12%29%5E2%29=20%2B49%2F24
6%28x%2B7%2F12%29%5E2=20%2B49%2F24
6%28x%2B7%2F12%29%5E2=480%2F24%2B49%2F24
6%28x%2B7%2F12%29%5E2=529%2F24 divide each side by 6
%28x%2B7%2F12%29%5E2=529%2F144 take square root of each side
x%2B7%2F12=%28%2B-23%29%2F12 subtract 7/12 from each side
x=%2B23%2F12-7%2F12=16%2F12=4%2F3
or
x=-23%2F12-7%2F12=-30%2F12=-5%2F2