SOLUTION: Tony had 13 bills in his wallet. They were all 5’s or 10’s. The total amount of money in his wallet was $90. How many 5’s in his wallet? heres another ? thanxs soooooo much!!!

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Tony had 13 bills in his wallet. They were all 5’s or 10’s. The total amount of money in his wallet was $90. How many 5’s in his wallet? heres another ? thanxs soooooo much!!!      Log On


   

Question 40012: Tony had 13 bills in his wallet. They were all 5’s or 10’s. The total amount of money in his wallet was $90. How many 5’s in his wallet?

heres another ? thanxs soooooo much!!!!!!!!!!!!!!!!!
There were 200 tickets sold at the school play. Tickets were $2 for students and $3 for adults. The total amount collected was $490. How many tickets were sold?
thanx
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Tony had 13 bills in his wallet. They were all 5’s or 10’s. The total amount of money in his wallet was $90. How many 5’s in his wallet"
Let number of $5 bills be "x".
Then number of $10 bills must be "13-x".
Value of the $5 bills is 5x dollars
Value of the $10 bills is 10(13-x)=(130-10x) dollars
EQUATION:
value + value = $90
5x+130-10x=90
-5x=-40
x=8 (number of $5 bills)
13-x=5 (number of $10 bills)
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There were 200 tickets sold at the school play. Tickets were $2 for students and $3 for adults. The total amount collected was $490. How many tickets were sold?
Let number of $2 tickets be "x"
Then number of $3 tickets is "200-x"
Value of the $2 tickets is 2x dollars
Value of the $3 tickets is 3(200-x)= 600-3x dollars
EQUATION:
value + value = $490
2x + 600-3x=490
-x=-110
x=110 (number of $2 tickets sold)
200-x=90 (number of $3 tickets sold)
Cheers,
Stan H.