SOLUTION: The function f(x) = 3x^3 - 2x^2 + x - 2 can be expressed as: a. (x+1) (x^2 + x + 2) b. (x-1) (x^2 + x + 2) c. (x+1) (3x^2 + x + 2) d. (x+1) (3x^2 + x + 2) I think it's C.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The function f(x) = 3x^3 - 2x^2 + x - 2 can be expressed as: a. (x+1) (x^2 + x + 2) b. (x-1) (x^2 + x + 2) c. (x+1) (3x^2 + x + 2) d. (x+1) (3x^2 + x + 2) I think it's C.       Log On


   

Question 391719: The function f(x) = 3x^3 - 2x^2 + x - 2 can be expressed as:
a. (x+1) (x^2 + x + 2)
b. (x-1) (x^2 + x + 2)
c. (x+1) (3x^2 + x + 2)
d. (x+1) (3x^2 + x + 2)
I think it's C. Am I right?

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Use limits to describe the end behavior of f(x) = 2 / (divided by) x^2 - 1 at values of x not in its domain.
Thanks for the help.
Found 2 solutions by MathLover1, ewatrrr:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

f%28x%29+=+3x%5E3+-+2x%5E2+%2B+x+-+2+........ -2x%5E2 we can write as -3x%5E2+%2Bx%5E2, and x+ as 2x-x+
f%28x%29+=+3x%5E3+-3x%5E2+%2Bx%5E2+%2B+2x-x+-+2+...now group them
f%28x%29+=+%283x%5E3+-3x%5E2+%29%2B%28x%5E2++-+x%29%2B+%282x+-+2%29+
f%28x%29+=+3x%5E2%28x+-+1%29%2Bx%28x++-+x%29%2B+2%28x+-+1%29
f%28x%29+=+%28x+-+1%29%283x%5E2%2Bx%2B+2%29

since you have
c. %28x%2B1%29+%283x%5E2+%2B+x+%2B+2%29
d. %28x%2B1%29+%283x%5E2+%2B+x+%2B+2%29
which are same, I guess you made mistake by typing d. I think you d should be
d. %28x-1%29+%283x%5E2+%2B+x+%2B+2%29

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

f(x) = 3x^3 - 2x^2 + x - 2 

f(1) = 3 - 2 + 1 - 2 = 0

  (x-1) is a factor

f(x)=(x-1) (x^2 + x + 2)



y = 2/(x^2-1)  x = 1 and x = -1 excluded from domain

 x= -1 and x=1 are the Blues lines on graph below