You can put this solution on YOUR website!
Since x-1 is a factor, then (x-1) should divide evenly into . We will use synthetic division to divide:
1 | 1 2 -5 -6
--- 1 3 -2
-------------
1 3 -2 -8
The remainder, in the lower right corner, is -8. This means that (x-1) is not a factor of ! (If (x-1) was a factor then the remainder would be zero.) So either the problem was given to you incorrectly or you posted it incorrectly.
If we pretend that we did get a reminder of zero, then the rest of the bottom line represents the other factor. The
1 3 -2
translates into
Then, to find the other factors, we would factor .