Question 373490: I would really appreciate your help! I need to find the values of p, r, and q. I have tried to simplify the binomial on the left side of the equals sign, but afterward none of the terms can be combined, leaving me with an unsolvable equation (I have not learned to solve quadratic equations and usually the equations cancel them out nicely):
(px+q)(2x+5)=6x^2+11x+r
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! FOILing ___ 2px^2 + (5p + 2q)x + 5q = 6x^2 + 11x + r
the quantities are equal , so the coefficients (for the x^2, x, and constant terms) are equal
2p = 6
5p + 2q = 11
5q = r
|
|
|
