SOLUTION: 1. (y-3)^3 - (y-3)^2 = 0 2. 2t^4 - 5t^2 + 3

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Question 366323: 1. (y-3)^3 - (y-3)^2 = 0
2. 2t^4 - 5t^2 + 3
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
1. %28y-3%29%5E2%28y-3-1%29+=+0,
%28y-3%29%5E2%28y-4%29+=+0. Therefore, the roots are 4 or 3 (multiplicity 2).
2. 2t%5E4+-+5t%5E2+%2B+3+=+0,
%282t%5E2-3%29%28t%5E2-1%29+=+0, therefore the roots are 1,-1, sqrt%283%2F2%29, or -sqrt%283%2F2%29.