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Question 35014: Solve for :
x^2-100/x^2+12x+20 times x^2+20x+100/x-10 = 18x+99/x+2
This is a real headache I can not figure it out
Answer by mszlmb(115) (Show Source):
You can put this solution on YOUR website! 
LOL wow that does look like a headache..
Solved by pluggable solver: EXPLAIN simplification of an expression |
Your Result:
YOUR ANSWER
- Graphical form:
simplifies to  - Text form: (x^2-100/x^2+12x+20)*(x^2+20x+100/x-10)=18x+99/x+2 simplifies to x^(4)+32*x^(3)+362*x+250*x^2-(x+20)*100/x+1901/x+998=0
- Cartoon (animation) form:
For tutors: simplify_cartoon( (x^2-100/x^2+12x+20)*(x^2+20x+100/x-10)=18x+99/x+2 )
- If you have a website, here's a link to this solution.
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DETAILED EXPLANATION
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Universal Simplifier and Solver
Done!
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hahaha WOW that WAS a headache.
OK now we've

Let's factor it out completely so I can make you go crazy. I firmly believe we shall have gone insane before the end of this problem.
X^3(x+32)+2x(181+125x)-100(x+20)/x+1901/x+998=0
MUAHAHA GO CRAZY WE SHALL! times X on both sides
X^4(x+32)+2x^2(181+125x)-100(x+20)+1901+998x=0
MEOW!!!
X^5+32X^4+362X+250X^2-100X-200+1901+998X=0
><(((-> MUST EAT FISH!
X^5+32X^4+250X^2+1260X=1901-200
WAAAAAAAAH!
X^5+32X^4+250X^2+1260X=1701
FACTOR TIME!
X^4(X+32)+10X(25X+126)=1701
X(X^3(X+32)+10(25X+126))=1701
WOOHOO! ARE YOUR EYES DISORIENTED YET?
cuz im going crazy! Ok, this is as far as I take you, which is two blessings and a curse. A blessing because now that all of the basics have been introduced 2 u u can figure out the rest and become a genius and a blessing cuz i gotta go to sleep dude. A curse cuz haha u still got that headache.
However, this @#$@ !@!#%$ !@#$%#@ @$#%#^%@ing math problem is such a peculiar one that I shall take it with me tomorrow to sql and try and work it out. If your problem drives me crazy, I'm suing u.
In the meantime, 1st off dont wait for me, repost ur problem.. If ur 2 layz just copy n pasts thie
'x^2-100/x^2+12x+20 times x^2+20x+100/x-10 = 18x+99/x+2
This is a real headache I can not figure it out'
Also, here are a few other problems to freakin drive u nuts. i still haven't figured these out. plz plz plz wen u find out how 2 tell me. they are entirely possible, im just a little dumb :)
EZ-->hard
1.)
SIX S, I, X, T, W, O, N, and E are independant 1 digit numbers. There
+TWO is only one answer, tell me what each equal (genius!). No, they
+ONE don't equal zero, and they are all diff.
------
NINE
2.)
ABCD Whence A, B, C, and D are each independant 1 dgt #'s. all diff
*ABCD= all nonzero positive integers.
____ABCD
ps just kidding about that suing thing :)
really, I'm sorry if you didn't get the answer you were looking for.. But if u were looking 4 a simplification :) it's there! kk bye :P I'll let u no if i figure it out in sql 2morrow
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