SOLUTION: If a-b=15 and a^2+b^2=137, find the numerical ab.

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Question 344427: If a-b=15 and a^2+b^2=137, find the numerical ab.
Answer by Jk22(389) About Me  (Show Source):
You can put this solution on YOUR website!
(a-b)^2=a^2-2ab+b^2=15*15=150+50+25=225

hence a^2+b^2-(a-b)^2=2ab=137-225=-(63+25)=-88

=> ab=-44