SOLUTION: Divide (30b^3+13b^2+38b+46)÷(6b+5)

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Question 330507: Divide (30b^3+13b^2+38b+46)÷(6b+5)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%2830b%5E3%2B13b%5E2%2B38b%2B46%29%2F%286b%2B5%29
First term:5b%5E2
5b%5E2%286b%2B5%29=30b%5E3%2B25b%5E2
Subtract that product from the original polynomial to get the remainder,
%2830b%5E3%2B13b%5E2%2B38b%2B46%29-%2830b%5E3%2B25b%5E2%29=+-12b%5E2%2B38b%2B46
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Second term:-2b
-2b%286b%2B5%29=+-12b%5E2-10b
Subtract that product from the remainder to get the new remainder,
%28-12b%5E2%2B38b%2B46%29-%28-12b%5E2-10b%29=48b%2B46
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Third term:8
8%286b%2B5%29=48b%2B40
Subtract that product from the remainder to get the new remainder,
%2848b%2B46%29-%2848b%2B40%29=6
No further division is possible.
Gather the terms and the remainder.
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%2830b%5E3%2B13b%5E2%2B38b%2B46%29%2F%286b%2B5%29=%285b%5E2-2b%2B8%29%2B6%2F%286b%2B5%29