SOLUTION: (3x-7) over (x^2-9) minus (x-1)over (x^2-9)

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Question 313017: (3x-7) over (x^2-9) minus (x-1)over (x^2-9)
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
3x-7)/(x^2-9) - (x-1)/ (x^2-9)
(3x-7)/(x+3)(x-3) - (x-1)/(x+3)(x-3)
LCM =(x+3)(x-3)
3x-7 -x+1 / (x+30(x-3)
2x-6 / (x+30(x-3)
2(x-3)/(x+3)(x-3)
2/(x+3)