SOLUTION: Find two positive real numbers that differ by 2 and have a product of 10.

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Question 311628: Find two positive real numbers that differ by 2 and have a product of 10.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
X=Y-2
XY=10
(Y-2)Y=10
Y^2-2Y=10
Y^2-2Y-10=0
Y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
Y=(2+-SQRT[-2^2-4*1*-10)'2*1
Y=(2+-SQRT[4+40])/2
Y=(2+-SQRT44)/2
Y=(2+-6.633)/2
Y=2+6.33)/2
Y=8.33/2
Y=4.3166 ANS.
X=4.3166-2=2.3166 ANS
Y=(2-6.633)/2
Y=-4.633/2
Y=-2.3166 ANS
X=-2.3166-2=-4.166 ANS.
PROOF:
4.3166*2.3166=10
10=10