Question 302246: Please help me solve this polynomial, in standard form: n + 3 + 3n^2.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve this polynomial, in standard form: n + 3 + 3n^2.
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3n^2 + n + 3 = 0
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Quadratic Function:
n = [-1 +- sqrt(1 - 4*3*3]/(2*3)
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n = [-1 +- sqrt(-35)]/6
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n = (-1/6)+(i/6)sqrt(35) or n = (-1/6)-(i/6)sqrt(35)
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Cheers,
Stan H.
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