SOLUTION: How would you work (4 - 5y + y^3 ) - ( 2-3y+y^2)

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Question 302123: How would you work (4 - 5y + y^3 ) - ( 2-3y+y^2)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How would you work (4 - 5y + y^3 ) - ( 2-3y+y^2)
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= 4 - 5y + y^3 - 2 + 3y - y^2
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= y^3 - y^2 - 2y +2
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Cheers,
Stan H.