SOLUTION: i am haveing trouble factoring this. can you please help me? {{{21x^5-24x^2-6x^4}}}

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Question 300782: i am haveing trouble factoring this. can you please help me? 21x%5E5-24x%5E2-6x%5E4
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What sort of trouble?

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
21x%5E5-24x%5E2-6x%5E4

First we rearrange the terms in descending order of
exponents of x, by swapping the 2nd and 3rd terms:

21x%5E5-6x%5E4-24x%5E2

We first look at 21, 6, and 24, and realize that the
largest integer that divides into all of them is 3,
and so that is the largest integer that can be
factored out

Then we look at the x%5E5, x%5E4 and x%5E2
and realize that the LARGEST exponent of x which can
be factored out is the SMALLEST one that occurs in any
term.  That is, x%5E2

So we factor out 3x%5E2

so we write this followed by an opening parenthesis:

3x%5E2%22%28%22

We divide 3 into 21 and get 7, and write this next:

3x%5E2%22%28%227

Then we divide x%5E2 into x%5E5 by subtracting exponents,
getting x%5E3, write that next to the 7 and we have this so far:

3x%5E2%22%28%227x%5E3

Now we look at second term of the original which is -6x%5E4

We divide 3 into -6 and get -2, and write this next:

3x%5E2%22%28%227x%5E3-2

Then we divide x%5E2 into x%5E4 by subtracting exponents,
getting x%5E4, write that next to the 2 and we have this so far:

3x%5E2%22%28%227x%5E3-2x%5E2

Now we look at last term of the original which is -24x%5E2

We divide 3 into -24 and get -8, and write this next:

3x%5E2%22%28%227x%5E3-2x%5E2-8

Then we divide x%5E2 into x%5E2, and since they are the
same, we just get 1, and we don't have to write anything, and
since this is the last term we have finished factoring, so we
write a closing parenthesis, and we are done:

3x%5E2%22%28%227x%5E3-2x%5E2-8%22%29%22

Edwin