SOLUTION: factor completely 2w^3x^4 -32w^3
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Question 298454
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factor completely 2w^3x^4 -32w^3
Answer by
user_dude2008(1862)
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2w^3x^4 -32w^3 = 2w^3(x^4-16) = 2w^3(x^2-4)(x^2+4) = 2w^3(x+2)(x-2)(x^2+4)