SOLUTION: 4a(3x+5)
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Question 29554
:
4a(3x+5)
Answer by
sdmmadam@yahoo.com(530)
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4a(3x+5)
=4aX(3x)+4aX(5) (expanding)
=12ax+20a
Note: Normally in problems it will be the other way around.
You will be given 12ax+20a
and pulling 4a common we write
12ax+20a = 4a(3x+5)