SOLUTION: 6t^2-18t
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Question 29366
:
6t^2-18t
Answer by
sdmmadam@yahoo.com(530)
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6t^2-18t
=6t(t-3)
Note: If 6t^2-18t
Then 6t(t-3)=0
6 cannot be zero
Either t= 0 or (t-3) = 0 which gives t=3
Therefore t=0 and t=3