SOLUTION: Factor by grouping x^2-y^2-ax-ay

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Question 276444: Factor by grouping x^2-y^2-ax-ay
Found 3 solutions by mananth, ikleyn, n2:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website!
x^2-y^2-ax-ay
(x+y)(x-y) - a(x+y)
(x+y){ x-y -ax+ay)
(x+y){ x-ax-y+ay}
(x+y){x(1-a)-y(1-a)}
(x+y){(1-a)(x-y)}
(x+y)(x-y)(1+a)

Answer by ikleyn(53742)   (Show Source):
You can put this solution on YOUR website!
.
Factor by grouping x^2-y^2-ax-ay
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        In the post by @mananth, factoring is made incorrectly, giving wrong answer.
        I came to bring a correct solution.

x^2-y^2-ax-ay = = (x+y)*(x-y) - a(x+y) = (x+y)*{x-y-a) This is the final ANSWER: x^2-y^2-ax-ay = (x+y)*(x-y-a).

Solved correctly.

Answer by n2(78)   (Show Source):
You can put this solution on YOUR website!
.
Factor by grouping x^2-y^2-ax-ay
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x^2-y^2-ax-ay = = (x+y)(x-y) - a(x+y) = (x+y){ x-y -a) This is the final ANSWER: x^2-y^2-ax-ay = (x+y)*(x-y-a).

Solved.