SOLUTION: If an object is propelled upward from ground level with an initial velocity of 224 feet per second, its height h in feet t seconds later is given by the equation h = 224t - 16t^2.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: If an object is propelled upward from ground level with an initial velocity of 224 feet per second, its height h in feet t seconds later is given by the equation h = 224t - 16t^2.       Log On


   



Question 269465: If an object is propelled upward from ground level with an initial velocity of 224 feet per second, its height h in feet t seconds later is given by the equation h = 224t - 16t^2. After how many seconds does the object hit the ground?

Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Set the function = 0 and solve. The ground is height = 0.
We get
(i) 224t+-+16t%5E2+=+0
divide by -16 to get
(ii) t%5E2+-+14+=+0
add 14 to get
(iii) t%5E2+=+14
take a square root to get
(iv) t+=+sqrt%2814%29
It is will take sqrt(14) or about 3.74 seconds to hit the ground