SOLUTION: I'm trying to find a polynomial for the perimeter and area of a rectangle. n+6 is on the top and n is on the right side.. I came up with n^2+12+36 for the area polynomial and (n

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I'm trying to find a polynomial for the perimeter and area of a rectangle. n+6 is on the top and n is on the right side.. I came up with n^2+12+36 for the area polynomial and (n      Log On


   

Question 256612: I'm trying to find a polynomial for the perimeter and area of a rectangle. n+6 is on the top and n is on the right side..
I came up with n^2+12+36 for the area polynomial and (n+6)^2+n^2 for the perimeter.. not sure if these are correct though. Please advise. thanks!
Phil
Found 3 solutions by drk, palanisamy, Alan3354:
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
Lets start with perimeter formula as
P+=+2L+%2B+2W
From the given information,. we have
P+=+2%28n%2B6%29+%2B+2%28n%29
which is
P+=+4n+%2B+12
--
Now we have the area formula as
A+=+LW
again, from the given, we get
A+=+%28n%2B6%29%28n%29
which is
A+=+n%5E2+%2B+6n

Answer by palanisamy(496) About Me  (Show Source):
You can put this solution on YOUR website!
Given the length of the rectangle = n+6
And the width of the rectangle = n
Perimeter = 2(n+6+n) = 2(2n+6) = 4n+12
And Area = (n+6)*n = n^2+6n

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Area = length * width
Area = n*(n+6)
-------------
Perimeter = 2L + 2W
P = 2n + 2n+12
P = 4n+12