SOLUTION: Find a value for K that will make 4x^2 + 6.4x + K a perfect square. Describe the procedure used which requires algebra and not trial and error.

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Question 255964: Find a value for K that will make 4x^2 + 6.4x + K a perfect square. Describe the procedure used which requires algebra and not trial and error.
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Find a value for K that will make 4x%5E2+%2B+6.4x+%2B+K a perfect square. Describe the procedure used which requires algebra and not trial and error.

4x%5E2+%2B+6.4x+%2B+K

Its square root must be a binomial with first term
the square root of 4x%5E2 or 2x, and
second term the square root of K or sqrt%28K%29

So we must have

%282x%2Bsqrt%28K%29%29%5E2=4x%5E2+%2B+6.4x+%2B+K

or

%282x%2Bsqrt%28K%29%29%282x%2Bsqrt%28K%29%29=4x%5E2%2B6.4x+%2B+K

or

4x%5E2%2B4x%2Asqrt%28K%29%2BK=4x%5E2%2B6.4x%2BK 

Add -4x%5E2-K to both sides:

4x%2Asqrt%28K%29=6.4x

Divide both sides by 4x

sqrt%28K%29=1.6

Square both sides

K=1.6%5E2

K=2.56 

That's the answer, and therefore

4x%5E2+%2B+6.4x+%2B+K becomes

4x%5E2+%2B+6.4x+%2B+2.56

which equals

%282x%2B1.6%29%5E2, a perfect square.

Edwin