SOLUTION: Factor:12w^2+10w-8

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Question 25395: Factor:12w^2+10w-8

Found 2 solutions by elima, AnlytcPhil:
Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
Begin by listing factors of 12 and 8;
12 = 1,12; 2,6; 3,4
8 = 1,8; 2,4
(6w+8)(2w-1)
=)

Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
Factor:12w^2+10w-8 

Here's one just like it.  Use it as a model to
factor yours by:

40x²+50x-15

First factor out the common factor of 5

5(8x²+10x-3)

Now to factor what is in the parentheses

Multiply the absolute values of the coefficient of the first 
term and last term

8·3 = 24

Think of two positive integers that have product 24 and
which have DIFFERENCE of the absolute value of the coefficient 
of the middle term, 10.  [Note: it's DIFFERENCE when the last
sign is -, but it's SUM when it's +] 

These as 12 and 2.

Now use 12 and 2 to rewrite the middle term + 10x.

+10x = +12x - 2x

So replace +10x by +12x - 2x

5[8x²+12x-2x-3]

Now factor by grouping.  

Factor the first two terms by taking out 4x

5[4x(2x+3)-2x-3]

Now factor the last two terms.  You can take out a -1.
[Always factor out a negative number if the third term is
negative

5[4x(2x+3)-1(2x+3)]

Now factor out (2x+3)

5[(2x+3)(4x-1)]

Now dispense with the brackets.

5(2x+3)(4x-1)

The answer to your problem is either

2(3x+4)(2x-1) or 2(2x-1)(3x+4)

Edwin
AnlytcPhil@aol.com