SOLUTION: If a^2 ≠ b^2 then (a^2 - b^2)/(b^2 -a^2) + (a - b)/(b - a) = a a - b /a + b b a^2 - b^2 c -2 d 0 e 2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: If a^2 ≠ b^2 then (a^2 - b^2)/(b^2 -a^2) + (a - b)/(b - a) = a a - b /a + b b a^2 - b^2 c -2 d 0 e 2      Log On


   



Question 253043: If a^2 ≠ b^2 then (a^2 - b^2)/(b^2 -a^2) + (a - b)/(b - a) =
a a - b /a + b b a^2 - b^2 c -2 d 0 e 2

Answer by JimboP1977(311) About Me  (Show Source):
You can put this solution on YOUR website!
Lets say for arguments sake that a=0. That means b must be greater or less than zero.
%28-b%5E2%29%2F%28b%5E2%29%29+%28-b%29%2Fb%29
%28%28-b%5E3%29%2B%28-b%5E3%29%29%2Fb%5E3
%28-2%28b%5E3%29%29%2Fb%5E3
-2