SOLUTION: how to factor: {{16n^4-1}}

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Question 251228: how to factor: {{16n^4-1}}
Answer by vksarvepalli(154) About Me  (Show Source):
You can put this solution on YOUR website!
using this %28x%5E2-y%5E2%29=%28x%2By%29%28x-y%29
we get %2816n%5E4-1%29=%284n%5E2-1%29%284n%5E2%2B1%29
4n^2-1 can be further divided into (2n+1)(2n-1)
so %2816n%5E4-1%29=%282n-1%29%282n%2B1%29%284n%5E2%2B1%29 Ans.