SOLUTION: Please factor 6y4-486

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Question 24979: Please factor 6y4-486
Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Common factor of "6"
6(y^4-81)
=6(y^2-9)(y^2+9)
=6(y-3)(y+3)(y^2+9)
Cheers,
Stan H.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Factor:
6y%5E4+-+486 First, factor a 6.
6%28y%5E4+-+81%29 The parentheses contain the difference of two squares.
6%28%28y%5E2%29%5E2+-+9%5E2%29 This can be factored.
6%28y%5E2+-+9%29%28y%5E2+%2B+9%29 Now the %28y%5E2+-+9%29 is the difference of two squares and can be factored.
6%28y+-+3%29%28y+%2B+3%29%28y%5E2+%2B+9%29
Normally we would stop here, but if you are into complex binomials, you can go one step farther. %28a%5E2+%2B+b%5E2%29 will factor as %28a+-+bi%29%28a+%2B+bi%29, so:
6%28y+-+3%29%28y+%2B+3%29%28y+-+3i%29%28y+%2B+3i%29 would be the complete factorisation.