Question 246719: Factor by grouping. Factor out GCF first
x^3y^3-2x^2y^2+3xy^2-6y^2
Help is greatly appreciated, thank you in advance. Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! x^3y^3-2x^2y^2+3xy^2-6y^2
first you can factor out y^2
so that you have
y^2(x^3y-2x^2+3x-6)
and that goes to
x^3y^3-(2x^2-3x+6)y^2