You can put this solution on YOUR website! Hello,
I'll help you with the first two. Let's see if you can do the rest of them.
x3+ax+3a+3x3 (I'm assuming x3 is x to the third power)
4x^3 + a(x+3)
18z+45+z2 rewritten as:
z^2 + 18z+45 This can be factored as:
(z+15)(z+3)
RJ Toftness
www.math-unlock.com