SOLUTION: (4x+1)(2x+7) Multiply. Show work and steps. (this was my answer but its wrong....what did I do wrong?) (4x+1)(2x+7) (F) 4*2=8x (O) 4*7=28x (I) 1*2=2x (L) 1*7= 7

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: (4x+1)(2x+7) Multiply. Show work and steps. (this was my answer but its wrong....what did I do wrong?) (4x+1)(2x+7) (F) 4*2=8x (O) 4*7=28x (I) 1*2=2x (L) 1*7= 7       Log On


   

Question 246224: (4x+1)(2x+7)
Multiply. Show work and steps.
(this was my answer but its wrong....what did I do wrong?)
(4x+1)(2x+7)
(F) 4*2=8x
(O) 4*7=28x
(I) 1*2=2x
(L) 1*7= 7
8x+28x+2x+7
=38x+7
Found 2 solutions by rfer, blwinbbbles:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
(4x+1)(2x+7)
8x^2+28x+2x+7
8x^2+30x+7

Answer by blwinbbbles(106) About Me  (Show Source):
You can put this solution on YOUR website!
You are almost right but:
4x * 2x = 8x^2
then you will have the 28x and the 2x and the 7
so your final equation is:
8x^2 + 30x + 7 = 0
Hope this helps
x^2 means x squared