SOLUTION: I need help on how to do this problem, please someone help me, i need to know this Factor by grouping. Factor out GCF first. x^3y^2 - 2x^2y^2 + 3xy^2 - 6y^2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need help on how to do this problem, please someone help me, i need to know this Factor by grouping. Factor out GCF first. x^3y^2 - 2x^2y^2 + 3xy^2 - 6y^2       Log On


   



Question 245983: I need help on how to do this problem, please someone help me, i need to know this
Factor by grouping. Factor out GCF first.
x^3y^2 - 2x^2y^2 + 3xy^2 - 6y^2

Found 2 solutions by richwmiller, Alan3354:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x^3y^2 - 2x^2y^2 + 3xy^2 - 6y^2
I see that y^2 is common to all terms.
so we can factor y^2(x^3-2x^2+3x-6)

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Factor by grouping. Factor out GCF first.
x%5E3y%5E2+-+2x%5E2y%5E2+%2B+3xy%5E2+-+6y%5E2+
= y%5E2%2A%28x%5E3+-+2x%5E2+%2B+3x+-+6%29
= y%5E2%2A%28x%5E2%2A%28x-2%29+%2B+3%28x-2%29%29
= y%5E2%2A%28x%5E2%2B3%29%2A%28x-2%29