Question 24587: Solve the system of equations by substitution: y= xsquared+2x-2 and y=3x+4
thanx Found 3 solutions by meghanjax13, MathTherapy, josgarithmetic:Answer by meghanjax13(2) (Show Source):
You can put this solution on YOUR website! y=x^2+2x-2
y=3x+4
substitute 3x+4 for y in the first equation.
3x+4=x^2+2x-2
Then solve.
0=x^2-x-6
Factor.
x=3
Substitute x back into the equation to find y.
y=3(3)+4
y=13
Check by substituting x and y into the first equation to make sure it works.
y=x^2+2x-2
13=3^2+2(3)-2
13=13
Hope I could help.
Solve the system of equations by substitution: y= xsquared+2x-2 and y=3x+4
thanx
*****
There're 2 sets of solutions: (3, 13), and (- 2, - 2), NOT 1 as the other person states.
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