SOLUTION: I need to solve 4w^2-6w-4=0
What I really need help understanding is how we come up with (2w-4)(2w+1)=0
I can get from there to 2 and -1/2.
If I can understand this, then I
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-> SOLUTION: I need to solve 4w^2-6w-4=0
What I really need help understanding is how we come up with (2w-4)(2w+1)=0
I can get from there to 2 and -1/2.
If I can understand this, then I
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Question 245842: I need to solve 4w^2-6w-4=0
What I really need help understanding is how we come up with (2w-4)(2w+1)=0
I can get from there to 2 and -1/2.
If I can understand this, then I can do the problem.
Thanks,
LeAnn Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website! LeAnn,
(2w-4) and (2w+1) are actually the factors of the original expession 4*w^2 - 6w - 4.
It takes some practice to be able to see how to factor a quadratic like this. Sometimes you will need to do some trial and error. For example you could have started with:
(4w+a)*(w+b)
but when multiplying back out you would have been unable to produce -6w for the middle term with any values for a and b with these coefficients on w.
Note also that the coefficent on the middle term (-6w) is negative so you know that a and b must have opposite signs.
Does this help?
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