SOLUTION: 3(y+4)=15

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Question 24481: 3(y+4)=15
Answer by askmemath(368) About Me  (Show Source):
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In order to remove the brackets we have to multiply every term within the brackets with the term immediately outside the bracket
3y+12 = 15
Subtracting 12 on both sides
3y = 3
Dividing by 3 throughout
y = 1