SOLUTION: Find three consecutive numbers where the product of the smaller two numbers is 37 less the square of the largest number. Thank you!

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find three consecutive numbers where the product of the smaller two numbers is 37 less the square of the largest number. Thank you!      Log On


   

Question 238489: Find three consecutive numbers where the product of the smaller two numbers is 37 less the square of the largest number.
Thank you!
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive numbers where the product of the smaller two numbers is 37 less the square of the largest number.
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1st: x-1
2nd: x
3rd: x+1
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Equation:
x(x-1) = (x+1)^2 - 37
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x^2-x = x^2+2x+1 - 37
-x = 2x-36
3x = 36
x = 12
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1st: x-1 = 11
2nd: x = 12
3rd: x+1 = 13
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Cheers,
Stan H.