SOLUTION: A quartic equation with integral coefficients has no cubic term and no constand term. If one root is 3-i the square root of 7, what are the other roots?

Question 231934: A quartic equation with integral coefficients has no cubic term and no constand term. If one root is 3-i the square root of 7, what are the other roots?
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
The equation described would be of the form:

From this equation we can factor out x^2:

From this we can see that x=0 is a double root (aka root of multiplicity 2). And if is a root, then its conjugate. , will also be a root.

So the 4 roots are: 0 (twice), and
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