SOLUTION: I am fairly new to algebra and I am having some trouble with this problem. I don't even know where to begin in solving it. Any help is greatly appreciated. Here is the pr

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am fairly new to algebra and I am having some trouble with this problem. I don't even know where to begin in solving it. Any help is greatly appreciated. Here is the pr      Log On


   



Question 228198: I am fairly new to algebra and I am having some trouble with this problem. I don't even know where to begin in solving it.
Any help is greatly appreciated.

Here is the problem:
f varies jointly as h and the square of q, and f = 36 when q = 2 and h = 3. Find k.

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
I am fairly new to algebra and I am having some trouble with this problem. I don't even know where to begin in solving it.
Any help is greatly appreciated.
Here is the problem:
f varies jointly as h and the square of q, and f = 36 when q = 2 and h = 3. Find k.

For all such problems, start with this:

Varying           "directly" or product of "jointlys" or 1 if none 
quantity  = k * ----------------------------------------------------------
                inversely variable or product of "inverselys" or 1 if none

In this problem the varying quantity is f.
there are no "directly"s or "inverselys", so we have
the product of the jointlys on top and 1 on the bottom:

f=k%2A%28hq%5E2%2F1%29

f=k%2Ahq%5E2

>>...f = 36 when q = 2 and h = 3...<<

Substitute these values:

f=k%2Ahq%5E2

%2836%29=k%2A%283%29%282%29%5E2

36=k%2A%283%29%284%29

36=k%2A12

36=12k

3=k

Edwin