SOLUTION: Hello, Simplify (-3x^2y^3)= -27x^6y^3 (my answer) 2(x^-3y^2)^2 = (2x^-3.2^y)2 (my answer) could you please tell me if i answered these correctly. Thanks

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hello, Simplify (-3x^2y^3)= -27x^6y^3 (my answer) 2(x^-3y^2)^2 = (2x^-3.2^y)2 (my answer) could you please tell me if i answered these correctly. Thanks      Log On


   

Question 22180: Hello,
Simplify
(-3x^2y^3)= -27x^6y^3 (my answer)
2(x^-3y^2)^2 = (2x^-3.2^y)2 (my answer)
could you please tell me if i answered these correctly.
Thanks
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
%28-3x%5E2y%5E3%29=+-27x%5E6y%5E3+ (my answer)

In the first case, notice that the parentheses are outside the exponent. This means that the 3 exponent just inside the parentheses applies ONLY to the y. You do NOT cube anything else. Your answer is not correct.

If the problem had been written:
%28-3x%5E2y%29%5E3+ with the parentheses on the INSIDE of the exponent, then you would be correct to say:
-27x%5E6y%5E3.

The expression +%28-3x%5E2y%5E3%29+ cannot be simplified.

2%28x%5E%28-3%29%2Ay%5E2%29%5E2+ I'm not sure what you tried to do in the second one. This is correct, if I've interpreted your problem correctly.
+2%28x%5E%28-6%29%2Ay%5E4+%29
2%281%2F%28x%5E6%29%29%2Ay%5E4%29+
+%282y%5E4%29%2F%28x%5E6%29+

R^2 at SCC