SOLUTION: How do I solve by substitution of linear equations? y=2 4x-2y=8

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How do I solve by substitution of linear equations? y=2 4x-2y=8      Log On


   



Question 214186: How do I solve by substitution of linear equations?
y=2

4x-2y=8

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
How do I solve by substitution of linear equations?
y=2

4x-2y=8

The following will the solve system of equations by substitution
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++0%5Cx+%2B+1%5Cy+=+2%2C%0D%0A++++4%5Cx+%2B+-2%5Cy+=+8+%29%0D%0A++The first equation is an easy equation for y: y+=+2%2F1.
Knowing y, we can substitute it into the second equation: 4%2Ax%2B-2%2A2%2F1+=+8. From here, x=%288--2%2A2%2F1%29%2F4Your answer: system%28+x=3%2C+y=2+%29+.



The solution is x=3 and y=2 or the point (3,2)

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J