Question 202283: if your car goes from 14 to 71 meters in 3 seconds, what is your acceleration?
Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! I believe the acceleration is expressed as change in velocity divided by change in time.
your change in velocity is from 14 to 71 = 57 meters.
your change in time is 3 seconds.
your acceleration should be 57/3 = 19 meters per second.
Answer by ikleyn(52957)  (Show Source):
You can put this solution on YOUR website! .
if your car goes from 14 to 71 meters in 3 seconds, what is your acceleration?
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From the Physics point of view, as well as from the Math point of view,
this problem is posed in EXTREMELY illiterate way.
Indeed, if 14 meters and 71 meter are positions of the points on the number line
(as the dimension of " meter " points to it), then velocity should be given at the start or at the finish
- only then the problem is posed properly.
But no velocity is given in the problem.
If 14 meters and 71 meter relate to velocity/speed, then the dimension should be " meters per second "
or something like this. But, again, this is not a case.
Therefore, the collection of words in this post is soup of words, or compote - on your choice.
But not a Math or a Physics problem.
Gibberish, in simple words.
Therefore, " solution " by @Theo makes no sense, so you better ignore it, for the peace in your mind.
He allegedly " determined " the acceleration, but even his dimensions
for acceleration are incorrect, so his writing is free composition with no sense.
Actually, @Theo calculated the average speed of the uniform move.
It assumes that the car moves uniformly with zero acceleration.
So, @Theo mixed everything in his post.
I may be speaking too harshly, but in my opinion it is better to tell the truth than to deceive.
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