SOLUTION: Find any variables for which the rational expression is undefined. 5m + 2 _________ m(squared) + m - 6 I tried to set the denominator equal to 0, then factor, but I am stuck

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find any variables for which the rational expression is undefined. 5m + 2 _________ m(squared) + m - 6 I tried to set the denominator equal to 0, then factor, but I am stuck       Log On


   



Question 199608This question is from textbook Beginning and Intermediate Algebra
: Find any variables for which the rational expression is undefined.
5m + 2
_________
m(squared) + m - 6
I tried to set the denominator equal to 0, then factor, but I am stuck on the factoring. Any help is appreciated.
This question is from textbook Beginning and Intermediate Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression m%5E2%2Bm-6, we can see that the first coefficient is 1, the second coefficient is 1, and the last term is -6.


Now multiply the first coefficient 1 by the last term -6 to get %281%29%28-6%29=-6.


Now the question is: what two whole numbers multiply to -6 (the previous product) and add to the second coefficient 1?


To find these two numbers, we need to list all of the factors of -6 (the previous product).


Factors of -6:
1,2,3,6
-1,-2,-3,-6


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -6.
1*(-6)
2*(-3)
(-1)*(6)
(-2)*(3)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 1:


First NumberSecond NumberSum
1-61+(-6)=-5
2-32+(-3)=-1
-16-1+6=5
-23-2+3=1



From the table, we can see that the two numbers -2 and 3 add to 1 (the middle coefficient).


So the two numbers -2 and 3 both multiply to -6 and add to 1


Now replace the middle term 1m with -2m%2B3m. Remember, -2 and 3 add to 1. So this shows us that -2m%2B3m=1m.


m%5E2%2Bhighlight%28-2m%2B3m%29-6 Replace the second term 1m with -2m%2B3m.


%28m%5E2-2m%29%2B%283m-6%29 Group the terms into two pairs.


m%28m-2%29%2B%283m-6%29 Factor out the GCF m from the first group.


m%28m-2%29%2B3%28m-2%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28m%2B3%29%28m-2%29 Combine like terms. Or factor out the common term m-2


So m%5E2%2Bm-6 factors to %28m%2B3%29%28m-2%29.


From here, you can use the factored form to solve for "m"