Question 199028: (14 over b-6) = 1/2 + (6 over b-8)
solve for b
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! 14/ (b-6) = 1/2 + 6/(b-8)
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14 / (b-6) -1/2 -6/ (b-8) = 0
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mult by 2(b-6)(b-8)
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2*14(b-8) -(b-6)(b-8) -2*6(b-6) = 0
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28b -224 -b^2 +14b -48 -12b +72 = 0
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-b^2 + 30b -200 = 0
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b^2 -30b +200 = 0
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(b-10)(b-20) =0
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b= 10, 20
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check
for 10,,,, 14/4 = 1/2 +6/2,,,,3.5=3.5,,,,ok
for 20,,,,14/14 =1/2 +6/12....1=1,,,,ok
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