SOLUTION:
4/2x^2-9x-35 and 3/4x^2+20x+25
I need to find the lcd of these two, i know i am supposed to factor them out, but i am having trouble finding something that wi
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-> SOLUTION:
4/2x^2-9x-35 and 3/4x^2+20x+25
I need to find the lcd of these two, i know i am supposed to factor them out, but i am having trouble finding something that wi
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Question 198409This question is from textbook Beginning Algebra
:
4/2x^2-9x-35 and 3/4x^2+20x+25
I need to find the lcd of these two, i know i am supposed to factor them out, but i am having trouble finding something that will factor. This question is from textbook Beginning Algebra
You can put this solution on YOUR website! 4/2x^2-9x-35 and 3/4x^2+20x+25
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2x^2-9x-35 = (2x + 5)*(x - 7)
4x^2+20x+25 = (2x + 5)*(2x + 5)
LCD = (2x + 5)*(2x + 5)*(x - 7)
