SOLUTION: Find the zeroes of f(x)=(x-2)3-3x+8. 2x3=x2+6x. X2+x=20

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Find the zeroes of f(x)=(x-2)3-3x+8. 2x3=x2+6x. X2+x=20      Log On


   

Question 197829: Find the zeroes of f(x)=(x-2)3-3x+8.
2x3=x2+6x.
X2+x=20
Answer by arallie(162) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=%28x-2%29%5E3-3x%2B8 {0,3}
2x%5E3=x%5E2%2B6x {-1.5,0,2}
X%5E2%2Bx=20 {4,-5}