SOLUTION: Hi, could you please help me with factoring? 4s^3+12s^2-64s-192= I am not sure what I am doing, but I am not coming up with the correct answer. Thanks

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Hi, could you please help me with factoring? 4s^3+12s^2-64s-192= I am not sure what I am doing, but I am not coming up with the correct answer. Thanks      Log On


   

Question 194979: Hi, could you please help me with factoring?
4s^3+12s^2-64s-192=
I am not sure what I am doing, but I am not coming up with the correct answer.
Thanks
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
4s%5E3%2B12s%5E2-64s-192 Start with the given expression


4%28s%5E3%2B3s%5E2-16s-48%29 Factor out the GCF 4


4%28%28s%5E3%2B3s%5E2%29%2B%28-16s-48%29%29 Group like terms


4%28s%5E2%28s%2B3%29-16%28s%2B3%29%29 Factor out the GCF 4s%5E2 out of the first group. Factor out the GCF -64 out of the second group


4%28%28s%5E2-16%29%28s%2B3%29%29 Since we have the common term s%2B3, we can combine like terms


4%28s-4%29%28s%2B4%29%28s%2B3%29 Factor s%5E2-16 to get %28s-4%29%28s%2B4%29


So 4s%5E3%2B12s%5E2-64s-192 completely factors to 4%28s-4%29%28s%2B4%29%28s%2B3%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
please help me with factoring?
4s^3+12s^2-64s-192
Factor the 1st two and the last two terms separately to get:
= 4s^2(s+3) - 64(s + 3)
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= (s+3)(4s^2- 64)
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= 4(s+3)(s^2 - 16)
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= 4(s+3)(s-4)(s+4)
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Cheers,
Stan H.