SOLUTION: solving a polynomial equation. 4y^3-7y^2-16y+28=0

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Question 189794: solving a polynomial equation.
4y^3-7y^2-16y+28=0
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
4y^3-7y^2-16y+28=0
y^2(4y-7)-4(4y-7)=0
(y^2-4)(4y-7)=0
(y+2)(y-2)(4y-7)=0
y=-2, y=2, y=7/4
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Ed