SOLUTION: Tryin to understand how to solve this problem. For all r&#8800;+2 r�2-5r+6 _______

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Question 188424: Tryin to understand how to solve this problem.
For all r≠+2
r�2-5r+6
________
r�2-4

Found 2 solutions by solver91311, vleith:
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

Let's get your terminology correct for starters. You can't really solve anything here because you don't have an equation -- there is no equals sign. You can, however, attempt to simplify this.

Factor both numerator and denominator polynomials:

Eliminate the common factor:

So you can now say:

So, why is there a restriction on the value of r ? You tell me.

John

Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website!

you can cancel the (r-2) as long as r!=2 (dividing by zero is undefined remember)

SOLUTION: Tryin to understand how to solve this problem. For all r&#8800;+2 r�2-5r+6 ________ r�2-4

SOLUTION: Tryin to understand how to solve this problem. For all r≠+2 r�2-5r+6 ________ r�2-4