SOLUTION: i just need help in trying to solve this division of polynomials: (24x2-19x+6)/(8x-1)

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Question 186269: i just need help in trying to solve this division of polynomials:
(24x2-19x+6)/(8x-1)
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve this division of polynomials:
(24x2-19x+6)/(8x-1)
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Using long division:
Quotient: 3x+2
Remainder: 8
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Cheers,
Stan H.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The 1st partial answer is
3x
3x%2A%288x+-+1%29+=+24x%5E2+-3x
Subtract 24x%5E2+-+3x from 24x%5E2+-+19x+%2B+6
getting -16x+%2B+6
The 2nd partial answer is
-2
-2%2A%288x+-+1%29+=+-16x+%2B+2
Subtract -16x+%2B+2 from -16x+%2B+6
getting 4
The answer is 3x+-+2+%2B+4%2F%288x+-+1%29 (4 is the remainder)
If you multiply 3x+-+2+%2B+4%2F%288x+-+1%29 by 8x+-+1,
you get 24x%5E2+-+19x+%2B+6