SOLUTION: Divide the polynomials. Please help me with this problem because I am getting stuck on it. Thanks. 2a^2-9a-5�2a+1=? Please can anyone help me with this problem? Thank you

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Question 167127This question is from textbook beginning algebra
: Divide the polynomials. Please help me with this problem because I am getting stuck on it. Thanks.

2a^2-9a-5�2a+1=?
Please can anyone help me with this problem? Thank you. This question is from textbook beginning algebra

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Divide the polynomials. Please help me with this problem because I am getting stuck on it. Thanks.
2a^2-9a-5 � 2a+1=?
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Do it just like long division.
2a^2/2a = a That's the first term
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a*(2a + 1) = 2a^2 + a
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2a^2- 9a-5
2a^2 + a
____ -10a-5 (subtracting gives -10a + 5)
So the 2nd term is -5
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2a^2-9a-5 � 2a+1 = a-5