SOLUTION: SOMEONE HELP PLEASE: y varies jointly as a and b and inversely as the square root of c. y = 48 when a = 4, b =8, and c = 36. Find y when a = 2, b = 7, and c = 16.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: SOMEONE HELP PLEASE: y varies jointly as a and b and inversely as the square root of c. y = 48 when a = 4, b =8, and c = 36. Find y when a = 2, b = 7, and c = 16.      Log On


   

Question 157936: SOMEONE HELP PLEASE:
y varies jointly as a and b and inversely as the square root of c. y = 48 when a = 4, b =8, and c = 36. Find y when a = 2, b = 7, and c = 16.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
y varies jointly as a and b and inversely as the y = 48 when a = 4, b =8, and c = 36square root of c. What you are not told is if there are some other factors as well. Let's assume there is some other constant involved. We will call that M
So
y+=+M+%2A%28a%2Ab%29%2F%28sqrt%28c%29%29+
You are told "y = 48 when a = 4, b =8, and c = 36"
So
48+=+M+%2A+4%2A8%2Fsqrt%2836%29+
48+=+M+%2A+32%2F6
48%2A6%2F32+=+M+
9+=+M
Our final equation is
y+=+9+%2A+a%2A+b%2Fsqrt%28c%29+
Now you are asked " Find y when a = 2, b = 7, and c = 16."
I bet you can take it from here :)